-20w=4w^2+25w

Solution for -20w=4w^2+25w equation:

-20w=4w^2+25w

We move all terms to the left:

-20w-(4w^2+25w)=0

We get rid of parentheses

-4w^2-20w-25w=0

We add all the numbers together, and all the variables

-4w^2-45w=0

a = -4; b = -45; c = 0;
Δ = b2-4ac
Δ = -452-4·(-4)·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-45}{2*-4}=\frac{0}{-8}
=0
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+45}{2*-4}=\frac{90}{-8}
=-11+1/4
$